Answer:
[tex]x =[/tex] ± [tex]2[/tex]
Step-by-step explanation:
Step 1: Solve using square root method
I'm not sure if y is supposed to be there or if there needs to be a 0 there. If we was to just find the value of x's then we can do the following.
Leave x by itself
[tex]0 = 9x^2 - 36\\0 + 36 = 9x^2 - 36 + 36\\36 = 9x^2[/tex]
Divide both sides by 9
[tex]\frac{36}{9} = \frac{9x^2}{9}[/tex]
[tex]4 = x^2[/tex]
Square root both sides
[tex]\sqrt{4} = \sqrt{x^2}[/tex]
± [tex]2 = x[/tex]
Answer: [tex]x =[/tex] ± [tex]2[/tex]
