kaztralgaming
contestada

A jet airplane travelling at the speed of 500 km / hr ejects its products of combustion at the speed of 1500 km / hr relative to the jet plane. What is the speed of the latter with respect to an observer on the ground?​

Respuesta :

given:

[tex]v{j} = 500[/tex]

[tex]vpj = - 1500[/tex]

solution:

[tex]vpj = vp - vj[/tex]

[tex] - 1500 = vp - 500[/tex]

[tex]vp = - 1000[/tex]

= 1000 km/h

mridiott

Speed of ejection of combustion products observed from ground is 1000km/h in direction opposite to the direction of motion of the jet airplane.

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