1.025 moles of NaCl are present in a solution with a molarity of 8.20M and 125 mL of solution. Details about molarity can be found below.
The number of moles of a solution can be calculated by multiplying the molarity of the solution by its volume. That is;
no of moles = molarity × volume
According to this question, a solution has a molarity of 8.20M and volume of 125 mL of solution.
no of moles = 8.20 × 0.125
no of moles = 1.025moles
Therefore, 1.025 moles of NaCl are present in a solution with a molarity of 8.20M and 125 mL of solution.
Learn more about number of moles at: https://brainly.com/question/14919968
#SPJ1