HELPPPP PLEASEEEE
How many moles of NaCl are present in a solution with a molarity of 8.20M and 125 mL of solution?

Respuesta :

1.025 moles of NaCl are present in a solution with a molarity of 8.20M and 125 mL of solution. Details about molarity can be found below.

How to calculate molarity?

The number of moles of a solution can be calculated by multiplying the molarity of the solution by its volume. That is;

no of moles = molarity × volume

According to this question, a solution has a molarity of 8.20M and volume of 125 mL of solution.

no of moles = 8.20 × 0.125

no of moles = 1.025moles

Therefore, 1.025 moles of NaCl are present in a solution with a molarity of 8.20M and 125 mL of solution.

Learn more about number of moles at: https://brainly.com/question/14919968

#SPJ1