find the area of the rhombus, I will give brainliest
12 in 9in
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Answer:
A = 216 in²
Step-by-step explanation:
the area (A) of a rhombus is calculated as
A = [tex]\frac{1}{2}[/tex] × d₁ × d₂ (d₁ and d₂ are the lengths of the diagonals )
the diagonals of a rhombus bisect each other , then
d₁ = 12 + 12 = 24
d₂ = 9 + 9 = 18
then
A = [tex]\frac{1}{2}[/tex] × 24 × 18 = 12 × 18 = 216 in²
Answer:
216
Step-by-step explanation:
Area of a rhombus=[tex]b * h[/tex] or [tex]\frac{d_1*d_2}{2}[/tex]
↓
First, add 12 and 12 together to get the length of one of the diagonals.
[tex]12 + 12 = 24[/tex]
Then add 9 and 9 together to get the length of the other diagonal.
[tex]9 + 9= 18[/tex]
Now you can substitute the variables with the corresponding values:
[tex]d_1 = 24[/tex]
[tex]d_2 = 18[/tex]
↓
[tex]\frac{24*18}{2}[/tex]
Now, multiply 24 and 18 together:
[tex]24 * 18 = 432[/tex]
Now divide 432 by 2:
[tex]\frac{432}{2}=216[/tex]
The area of the rhombus is 216.
Hope this helps! Let me know if you have any questions. Have a great day!