Now
Ideal gas equation
[tex]\\ \rm\Rrightarrow PV=nRT[/tex]
[tex]\\ \rm\Rrightarrow 112=n(8.314)(398)[/tex]
[tex]\\ \rm\Rrightarrow n=0.033mol[/tex]
Answer:
[tex]0.03384\ mol[/tex]
Explanation:
Step 1: Determine important information
Ideal gas law → [tex]PV=nRT[/tex]
At the end of the problem statement we can see that the pressure is [tex]1.0\ atm[/tex]. V is the volume which is given as [tex]112\ L[/tex]. n is the amount of substance which is what we are trying to find. R is the ideal gas constant is the same for every problem which is [tex]8.3145\ J * mol^{-1}*K^{-1}[/tex]. Finally, T is the temperature which is given as [tex]125\ C[/tex] but we have to convert to kelvins which we get [tex]398\ K[/tex].
Step 2: Plug in the information and solve
[tex]PV=nRT[/tex]
[tex](1.0\ atm)*(112\ L) = n*(8.3145\ J * mol^{-1}*K^{-1})*(398\ K)[/tex]
[tex]112=n*(3,309.171)[/tex]
[tex]\frac{112}{(3,309.171)}=\frac{n*(3,309.171)}{(3,309.171)}[/tex]
[tex]0.03385\ mol = n[/tex]
Answer: [tex]0.03384\ mol[/tex]
