Respuesta :
[tex]QUESTION:[/tex]
a body of mass 10kg at rest is subjected force of 16N. Find the kinetic energy at end of 20s.
[tex]SOLUTION:[/tex]
[tex]Given[/tex] [tex]that:[/tex]
- Mass = 10kg
- Initial Velocity (u) = 0
- Force = 16 N
- Time = 20 seconds
» Finding for the acceleration:
[tex]a=F/m[/tex]
[tex]a=16N/10kg[/tex]
[tex]a=1.6/s^2[/tex]
» Then velocity after 20 seconds will be:
[tex]v=u+at[/tex]
[tex]v=0+1.6m/s^2(20s)[/tex]
[tex]v=32/s^[/tex]
» Now , Finding for the kinetic energy:
[tex]K=1*2mv^2[/tex]
[tex]K=1/2(10)(32)^2[/tex]
[tex]K=5(1024)[/tex]
[tex]K=5120[/tex] [tex]J[/tex]
[tex]ANSWER:[/tex]
- The kinetic energy aquired by the body is 5,120 Joules
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[tex] \large \sf \underline{Problem:}[/tex]
- A body of mass 10kg at rest is subjected force of 16N. Find the kinetic energy at end of 20s.
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[tex] \large \sf \underline{Answer:}[/tex]
[tex] \huge \qquad \quad \sf{5,120 \: Joules}[/tex]
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[tex] \large \sf \underline{Solution:}[/tex]
Firstly, find the acceleration:
- [tex]\sf{A = F/m}[/tex]
- [tex]\sf{A = 16N/10kg}[/tex]
- [tex]\sf \pmb{A = 1.6m/s^2}[/tex]
Secondly, the velocity after 20 seconds will be:
- [tex]\sf{V =u+at}[/tex]
- [tex]\sf{V =0+1.6m/s^2(20s)}[/tex]
- [tex]\sf \pmb{V =32m/s}[/tex]
Lastly, find the kinetic energy:
- [tex]\sf{K=1/2mv^2}[/tex]
- [tex]\sf{K=1/2(10)(32)^2}[/tex]
- [tex]\sf{K=5(1024)}[/tex]
- [tex]\sf{\underline{\underline{\pmb{K=5120\:J}}}}[/tex]
Hence, the kinetic energy at the end is 5,120 Joules.
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