Respuesta :
The boiling point of a solution of 6.4 g of vanillin in 50.0g of ethanol is 77.47 degree C.
How do we calculate boiling point?
Change in boiling point of solution will be calculated by using the below formula:
ΔTb = (Kb)(m), where
ΔTb = change in temperature
Kb = elevation constant = 1.22 degrees c/m
m is the molality of the solution and it will be define as the number of moles of solute present in per kilogram of solvent.
Molality of vanillin in ethanol will be calculated after calculating the moles of vanillin.
Moles of vanillin = 6.4g / 152.12g/mol = 0.042 mol
m of vanillin = 0.042mol / 0.05kg = 0.84m
On putting all these values on the above equation we get,
ΔTb = (1.22)(0.84) = 1.0248 degree C
Given that, boiling point of ethanol = 78.5 degree C
So the boiling point of vanillin = 78.5 - 1.0248 = 77.47 degree C
Hence, the boiling point of a solution of vanillin is 77.47 degree C.
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