In a sealed and rigid container, a sample of gas at 2.50 atm and 60.0 °C is cooled to 20.0 °C. What is the pressure (in atm) of the gas at 20.0 °C?

Respuesta :

Answer: ≈ 0.833 atm

Explanation:

2.5 / 60 = 20 / P

In order to solve for P, we must find divide 2.5 by 60 which gives us 0.04167. Then we multiply by 20 to get 0.833 atm