Answer:
c)20 1/4
Step-by-step explanation:
[tex]9x^{2}y^{-2}[/tex]
If We replace x by -3 and y by 2 we get :
[tex]9\left( -3\right)^{2} \left( 2\right)^{-2}[/tex]
Or we have :
[tex]\left( -3\right)^{2} =9\ \text{and} \ \left( 2\right)^{-2} =\frac{1}{2^{2}} =\frac{1}{4}[/tex]
then
[tex]9\left( -3\right)^{2} \left( 2\right)^{-2}=9\times9\times\frac{1}{4} = \frac{81}{4}[/tex]
on the other hand :
[tex]\frac{81}{4} =\frac{80+1}{4} =\frac{80}{4} +\frac{1}{4} =20+\frac{1}{4}=20\frac{1}{4}[/tex]
