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A student slides a box across the floor to his friend. The mass of the box is 25 kg and the
coefficient of kinetic friction between the floor and the box is 0.52. If the initial velocity
of the box is 7.0 m/s, how far will the box slide before it stops?

Respuesta :

onyebuchinnaji

The distance traveled by the box before stopping, when the student slides the box across the floor  to his friend, at the given coefficient of kinetic friction is 4.8 m.

Acceleration of the box

The acceleration of the box across the floor is determined by applying Newton's second law of motion.

∑F = ma

-Ff = ma

-μmg = ma

-μg = a

-(0.52 x 9.8) = a

- 5.1 m/s² = a

Distance traveled by the box before stopping

The distance traveled by the box before it stops is calculated  as follows;

v² = u² + 2as

where;

  • v is the final velocity of the box when it stops = 0

0 = (7)² + 2(-5.1)s

0 = 49 - 10.2s

10.2s = 49

s = 49/10.2

s = 4.8 m

Thus, the distance traveled by the box before it stops is 4.8 m.

Learn more about acceleration here: https://brainly.com/question/14344386

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