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If the concentration of sn2+ in the cathode compartment is 1.30 m and the cell generates an emf of 0.21 v , what is the concentration of pb2+ in the anode compartment?

Respuesta :

By the use of the Nernst equation, the concentration of the lead solution is 4.8 * 10^-8 M.

What is Nernst equation?

The Nernst equation is the equation that is used to obtain the EMF of a cell under non standard conditions.

Now;

E°cell = -0.01 V

Ecell = 0.21V

[sn2+] = 1.30 M

[pb2+] = ?

From;

Ecell = E°cell  - 0.0592/n logQ

The equation is; Sn^+ + Pb ----> Sn(s) + Pb^2+

0.21 =  -0.01  - 0.0592/2 log(x/1.30 )

0.21 + 0.01 = -0.0592/2 log(x/1.30 )

0.22/-0.0296 =  log(x/1.30 )

-7.43 =  log(x/1.30 )

Antilog(-7.43) = x/1.3

x = 4.8 * 10^-8 M

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