Here,
let the forth degree of the quadrilateral be y
Then,
90° +90° +68.5° + y =360° (all the interior angle of a quadrilateral is 360°)
or, 248.5+ y=360°
or, y = 360° - 248.5°
or, y= 111.5°
Again, the second angle of the triangle be a
Then,
a=111.5(vertically opposite angle)
Lastly,
29° + 111.5° + x = 180°(all the interior angle of a triangle is 180°)
or, 140.5° + x = 180°
or, x =180° - 140.5°
or, x=39.5°
