Respuesta :

Zeros are

  • (0,0)
  • (-3,0)
  • (-4,0)

Write in factor form and solve

  • (x-0)(x-(-3))(x-(-4))=0
  • x(x+3)(x+4)=0
  • x[x(x+4)+3(x+4)]=0
  • x(x²+4x+3x+12)=0
  • x(x²+7x+12)=0
  • x³+7x²+12x=0

Points given (-2,16)

Solve for n

  • n(x³+7x²+12x)=y

On solving we get

  • n=-4

So the function is

  • y=-4(x³+7x²+12x)
  • y=-4x³-28x²-48x
fieryanswererft

Answer:

-4x³ - 28x²- 48x

Explanation:

  • x-intercept: (-4, 0), (-3, 0), (0, 0)

→ so equation: a(x+4)(x+3)(x+0)

  • point given: (-2, 16)

→ substitute these points to find a

  • a(-2+4)(-2+3)(-2) = 16
  • a = -4

so the graphed cubic equation:

  • -4(x+4)(x+3)(x+0)
  • -4x³ -28x²-48x

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