Im stuck on this problem. Please explain how you got your answer
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The function [tex]y=0.3^x[/tex] represents exponential growth with the initial value equal to 1, the decay factor equal to 0.3, and the rate equal to 0.7.
The formula for the Population Growth Equation is:
[tex]P_f=P_o*(1+\frac{R}{100}) ^t[/tex]
Pf= future population
Po=initial population
r=growth rate
t= time (years)
growth or decay factor = (1 ±r)
When 1+R > 1, the equation represents growth, while 1+R < 1 the equation represents decay.
The question gives:
[tex]y=0.3^x[/tex], then
Pf=y
Po= 1
[tex](1+\frac{R}{100}) =0.3[/tex] , thus
[tex](100+R}) =30\\ \\ R=-100+30\\ \\ R=-70[/tex]
r= -70%= -0.7
decay factor= (1-0.7)=0.3
Therefore,
1+R will be = 1+(-0.7)=1 - 0.7 =0.3
When 1+R >1, the function represents exponential growth.
Read more about the exponential function here:
brainly.com/question/8935549