Respuesta :

Answer:

12.979 m:L (3 d.p.)

Explanation:

Combined Gas Law

[tex]\sf \dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}[/tex]

Temperature must be in kelvins (K).

To convert Celsius to kelvins, add 273.15.

Volume can be in any unit.

Given values:

  • P₁ = 0.837 atm
  • V₁ = 17.5 mL
  • T₁ = 48°C = 48 + 273.15 = 321.15 K
  • P₂ = 0.995
  • V₂ =
  • T₂ = 10°C = 10 + 273.15 = 283.15 K

Rearrange the equation to isolate V₂:

[tex]\implies \sf V_2=\dfrac{P_1V_1T_2}{P_2T_1}[/tex]

Substitute the given values into the equation:

[tex]\implies \sf V_2=\dfrac{0.837 \cdot 17.5 \cdot 283.15}{0.995 \cdot 321.15}[/tex]

[tex]\implies \sf V_2=12.979\:mL\:(3\:d.p.)[/tex]

Therefore, the volume at 10°C will be 12.979 mL (3 d.p.).

Learn more about the Combined Gas Law here:

https://brainly.com/question/28143218

Temperatures

  • T1=273.+48=321K
  • T2=273+10=283K

Apply combined gas law

[tex]\\ \rm\dashrightarrow \dfrac{P1V1}{T1}=\dfrac{P2V2}{T2}[/tex]

[tex]\\ \rm\dashrightarrow V2=\dfrac{P1V1T2}{P2T1}[/tex]

[tex]\\ \rm\dashrightarrow V2=\dfrac{0.837(17.5)(283)}{0.995(321)}[/tex]

[tex]\\ \rm\dashrightarrow V2=12.978mL[/tex]

[tex]\\ \rm\dashrightarrow V2=12.98mL[/tex]