Let's use some identities to help us solve
[tex]x = 4 cos(t)\\\frac{x}{4} =cos(t)\\\\y = 5sin(t)\\\frac{y}{5} =sin(t)[/tex]
We know --> [tex]sin^2(t)+cos^2(t) = 1[/tex]
So:
[tex]\frac{y^2}{5^2} +\frac{x^2}{4^2}=1\\ \frac{x^2}{16} +\frac{y^2}{25} =1[/tex]
Thus the choice is the second choice
An equation is formed of two equal expressions. The correct option is B.
An equation is formed when two equal expressions are equated together with the help of an equal sign '='.
Given two of the equations which can be rewritten as shown below,
x = 4 cos(t)
x/4 = cos(t)
Squaring both sides of the equation,
x²/16 = cos²(t)
y = 5 sin(t)
y/5 = sin(t)
Squaring both sides of the equation,
y²/25 = sin(t)
y²/25 = sin²(t)
Adding the two of the given equations we will get,
(x²/16) + (y²/25) = cos²(t) + sin²(t)
(x²/16) + (y²/25) = 1, this is because cos²(x) + sin²(x) = 1
The rectangular form of the parametric equations x=4cos(t)and y=5sin(t) is (x²/16) + (y²/25) = 1.
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