AC = BC, <ACB = 40°, <AMN = 25° <CPM = ?

Answer:
∠ CPM = 135°
Step-by-step explanation:
given AC = BC , then Δ ABC is isosceles with base angles congruent , then
∠ ABC = [tex]\frac{180-40}{2}[/tex] = [tex]\frac{140}{2}[/tex] = 70°
the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles, then
∠ AMN + ∠ BPM = ∠ ABC , that is
25° + ∠ BPM = 70° ( subtract 25° from both sides )
∠ BPM = 45°
∠ CPM and ∠ BPM are adjacent angles on a straight line and sum to 180°
∠ CPM + 45° = 180° ( subtract 45° from both sides )
∠ CPM = 135°