I need help with the problem below. I will give brainliest
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Answer:
π + 2
Step-by-step explanation:
x² + y² - 4x - 4y + 4 = 0
(x² - 4x + 4) + (y² - 4y + 4) + 4 - 4 - 4 = 0
(x - 2)² + (y - 2)² = 4
So the radius of the circle = 2, center C(2, 2)
Are a of AMNB = area of semi-circle - area of segment AB
= area of semi-circle - (area of quarter circle ABC - area of triangle ABC)
= area of quarter circle ABC + area of triangle ABC
= π(2)²/4 + 2*2/2
= π + 2