Answer:
lower
Explanation:
For a spontaneous process, the standard Gibbs free energy change has to be less than zero:
∆G° < 0 → spontaneous
∆G° > 0 → non- spontaneous
∆G° = 0 → system is at equilibrium
For a negative change in standard Gibbs free energy, the Gibbs free energy of the products has to be lower than that of the reactants since Gibbs free energy change is the standard Gibbs free energy of products minus that of the reactants.
[tex]\boxed{∆G= G°(products) -G°(reactants)}[/tex]
Mathematical derivation:
G°(products) -G°(reactants) < 0
G°(products) < G° (reactants)
✩ Note that in the image attached, the Gibbs free energy change is usually denoted by a single-headed arrow, from reactants to products.
What is free energy?
Standard state conditions
Spontaneity