Please help me out it’s urgent
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Perimeter:
[tex]6y + 12[/tex]
Area:
[tex] {2y}^{2} + 12y[/tex]
Step-by-step explanation:
Perimeter of a rectangle : P= 2( L + w)
in this case it would be 2(y+6) + 2(2y)
= 2y+12 + 4y
simplified to 6y +12
Area of a rectangle : A= LW
=(y+6)(2y)
We foil and get
[tex] {2y}^{2} + 12y[/tex]