72.06 grams is the mass of produced H₂O in the given reaction.
Mass of any substance can be calculated by using moles as:
n = W/M, where
W = required mass
M = molar mass
Given chemical reaction is:
NH₄NO₃ → N₂O + 2H₂O
From the stoichiometry of the reaction it is clear that:
1 mole of NH₄NO₃ = produce 2 mole of H₂O
Given mass of NH₄NO₃ = 160.1 g
Molar mass of NH₄NO₃ = 80.03 g/mole
Mole of NH₄NO₃ = 160.1 g / 80.03 g/mole = 2 moles
2 moles of NH₄NO₃ = produce 2 × 2 = 4 moles of H₂O
Molar mass of H₂O = 18.01 g/mol
So, required mass of H₂O will be calculated as:
W = 4mol × 18.01 g/mol = 72.06 grams
Hence, 72.06 grams is the mass of H₂O.
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