The chemical equation below shows the decomposition of ammonium nitrate (NH4NO3). NH4NO3 Right arrow. N2O 2H2O A chemist who is performing this reaction starts with 160. 1 g of NH4NO3. The molar mass of NH4NO3 is 80. 03 g/mol; the molar mass of water (H2O) is 18. 01 g/mol. What mass, in grams, of H2O is produced? 9. 01 grams 18. 01 grams 36. 03 grams 72. 06 grams.

Respuesta :

72.06 grams is the mass of produced H₂O in the given reaction.

How we calculate mass from moles?

Mass of any substance can be calculated by using moles as:

n = W/M, where

W = required mass

M = molar mass

Given chemical reaction is:

NH₄NO₃ → N₂O + 2H₂O

From the stoichiometry of the reaction it is clear that:

1 mole of NH₄NO₃ = produce 2 mole of H₂O

Given mass of NH₄NO₃ = 160.1 g

Molar mass of NH₄NO₃ = 80.03 g/mole

Mole of NH₄NO₃ = 160.1 g / 80.03 g/mole = 2 moles

2 moles of NH₄NO₃ = produce 2 × 2 = 4 moles of H₂O

Molar mass of H₂O = 18.01 g/mol

So, required mass of H₂O will be calculated as:

W = 4mol × 18.01 g/mol = 72.06 grams

Hence, 72.06 grams is the mass of H₂O.

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