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A crate is released from the highest point of a 12 m long ramp inclined at 60° with the horizontal. The motion is frictionless. What is the speed of the crate at the base of the ramp?​

Respuesta :

indrawboy

law of conservation of mechanical energy

PE1 = Ek2

mgh=1/2mv²

h = 12 sin 60

[tex]\tt v=\sqrt{2gh}=\sqrt{2\times 9.8\times 12\times sin~60}=14.27~m/s[/tex]

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