Using the given equation, it is found that it lands on the ground after 0.875 seconds.
What is the equation for the projectile's height?
It is given by:
[tex]h(t) = -16t^2 + vt + h[/tex]
In which:
- v is the initial velocity.
In this problem, considering that the projectile jumps straight into the air with an initial vertical velocity of 14 ft/s, the parameters are v = 14 and h = 0, hence:
[tex]h(t) = -16t^2 + 14t[/tex]
It lands on the ground when h(t) = 0, hence:
[tex]-16t^2 + 14t = 0[/tex]
[tex]t(-16t + 14) = 0[/tex]
Then:
[tex]16t = 14[/tex]
[tex]t = \frac{14}{16}[/tex]
[tex]t = 0.875[/tex]
It lands on the ground after 0.875 seconds.
More can be learned about equations at https://brainly.com/question/25537936
