How much of the 0.2M stock solution of NaCl did you need to make a 100mL
dilution of NaCl at final concentration 0.05M? Please give your answer in units of
MILLILITERS, however do not explicitly include any units in your answer.

Respuesta :

Oseni

The amount of 0.2 M stock NaCl that would be required to make 100 mL, 0.05 M NaCl would be 25 mL

Dilution

Using the equation of dilution:

M1V1 = M2V2

In this case, M1 = 0.2M, V1 = ?, M2 = 0.05 M, V2 = 100 mL

V1 = M2V2/M1

            = 0.05 x 100/0.2

               = 25 mL

The volume of the stock solution needed is 25 mL

More on dilution can be found here: https://brainly.com/question/13844449