First of all find the total area and then subtract the area of circle from the area of rectangle, It will be easier that way...
[tex]\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}[/tex]
Finding area of rectangle:
[tex] \qquad \bf \implies \: area = length \times breadth[/tex]
- Length = 3 cm
- Breadth = 4 cm
[tex] \qquad \tt \blue\looparrowright \purple{area = 3 \times 4} [/tex]
[tex] \qquad \tt \blue\looparrowright \purple{area = 12 \: {cm}^{2} } [/tex]
Finding area of circle:
[tex] \qquad \bf \implies \: area = \pi {r}^{2} [/tex]
[tex] \qquad \tt \red\looparrowright \green{area = \frac{22}{7} \times {1}^{2} } [/tex]
[tex] \qquad \tt \red\looparrowright \green{area = \frac{22}{7} \times 1} [/tex]
[tex] \qquad \tt \red\looparrowright \green{area = 3.14 \: {cm}^{2} } [/tex]
Find the area of shaded region now,
[tex] \qquad \bf \implies \: area =area \: of \: rectangle - area \: of \: circle[/tex]
- Area of rectangle = 12 cm²
- Area of circle = 3.14 cm²
[tex] \qquad \tt \pink\looparrowright \orange{area = 12 - 3.14 } [/tex]
[tex] \qquad \tt \pink\looparrowright \orange{area = 8.86} [/tex]
➪ Thus, The area of the shaded region is 8.86 cm²...~
