Answer:
[tex]4x² + 2y² + x²y² + 8 \\arranging \: them \\ 4 {x}^{2} + {x}^{2} {y}^{2} + 2 {y}^{2} + 8 \\ {x}^{2} (4 + {y}^{2} ) + 2(y^{2} + 4) \\ ({x}^{2} + 2)(y^{2} + 4)[/tex]
Answer:
(4 + y^2) ( x^2 + 2)
Step-by-step explanation:
irst rearrange the terms
4x^2 + x^2 y^2 + 2y^2 + 8
then factorise
x2 ( 4 + y^2) + 2 ( y^2 + 4)
group like terms together and insert the remaining terms into a bracket
(4 + y^2) ( x^2 + 2)
