Answer:
B) 4 m/s²
Explanation:
[tex] \boxed{ \sf{ F= m \times a}}[/tex]
Here,
Substituting the respective values for F and m:
==> 220 = 55 × a
==> 220 = 55 × a
dividing the equation by 55:
==> 4 = a
Therefore, an object of 55 kg when pulled across a frictionless surface by a force of 220 N accelerates at 4 (m/s)/s