Answer:
[tex]\frac{3x + 1}{5}[/tex]
Step-by-step explanation:
y = [tex]\frac{5x-1}{3}[/tex]
make x the subject
3y = 5x - 1
3y + 1 = 5x
[tex]\frac{3y + 1}{5}[/tex] = x
now switch x with yso,
[tex]\frac{3x + 1}{5}[/tex] (ans)
