A car of mass 1000 kg is heading east at 25 m/s. It collides with a car of mass 1200 kg heading north at 30 m/s. When the cars collide, they stick together.

d. At what angle do the cars move after the collision? (2 points)

Here it's given that a car of mass 1000kg moving with velocity of 25m/s North . Another car of mass 1200kg is moving with velocity 30m/s East.

So that ,

[tex]v_{1}= 25m/s \ E= 25 \hat{i} m/s [/tex]

And ,

[tex]v_{2}= 30m/s \ N = 30 \hat{j} m/s [/tex]

See attachment .

From Triangle law of vector addition , the resultant of both vectors will be given by third side of the triangle taken in opposite direction.

So , if the resultant velocity makes an angle [tex]\theta[/tex] . Then ,

[tex] tan\theta = \dfrac{v_2}{v_1} [/tex]

Substituting the respective values,

[tex]tan\theta =\dfrac{30m/s}{25m/s} [/tex]

Simplify ,

[tex]tan\theta =\dfrac{6}{5}[/tex]

Take arctan both sides ,

[tex]\theta = tan^{-1}\bigg(\dfrac{6}{5}\bigg)[/tex]

Hence the cars move at an angle of tan-¹(6/5) NE after the collision .

A car of mass 1000 kg is heading east at 25 m/s. It collides with a car of mass 1200 kg heading north at 30 m/s. When the cars collide, they stick together. d. At what angle do the cars move after the collision? (2 points)

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A car of mass 1000 kg is heading east at 25 m/s. It collides with a car of mass 1200 kg heading north at 30 m/s. When the cars collide, they stick together.

d. At what angle do the cars move after the collision? (2 points)