PLEASE HELP ME!!! WILL MARK BRAINLIEST!! THX!The equation below represent the path of an object. Use it to answer the following (round to 3 decimal places...no units)
h(t)=-4.9t^2+75t+150
(a) When does the object hit the ground? ___

(b) What is the maximum height of the object? ___

(c) When does the object reach its maximum height? ___

(d) What is the height of the object at 4.67 seconds? ___

(e) How many times does the object reach a height of 149 meters? ___(enter a numeric value)

(f) When does the object reach a height of 356 meters? ___ and ___(enter the smaller value first)

Respuesta :

Answer:

see below

Step-by-step explanation:

h=−4.9t^2 +39.2t

When will if fall back to the ground

When will h=0

0 =−4.9t^2 +39.2t

Factor out a -t

0 = -t (4.9t -39.2)

Using the zero product property

-t =0     4.9t - 39.2 =0

t =0     4.9t = 39.2

               t =39.2 /4.9

              t =8

It will reach the ground again at 8 seconds

The maximum height is halfway between the zeros

(0+8)/2 = 4

It will reach the max height at 4 seconds, substituting this in to find the max height

h=−4.9 (4)^2 +39.2(4)

h = 78.4 meters

This will only be applicable between t=0 and t=8 seconds

0≤t≤8 seconds