Answer:
1={5 and 3} 2={0} 3={0.209 and 4.791} 4={-3 and 4} 5={1 and 9} 6={-4.303 and -0.697}
Step-by-step explanation:
Your probably confused on what a, b, and c means.
The problems are written like this.
[tex]ax^2+bx+c=0[/tex]
That formula finds the zeros.
For example 1:
[tex]x^2-8x+15=0\\ax^2-bx-c\\a=1\\b=-8\\c=15[/tex]
Then use the formula
[tex]x=\frac{-b+-\sqrt{b^2-4ac} }{2a} \\\\x=\frac{-(-8)+-\sqrt{-8^2-4(1)(15)} }{2} \\x=\frac{8+-\sqrt{64-60} }{2} \\\\x=\frac{8+-2}{2}\\[/tex]
If plus then 5, if minus then 3
CHECK:
[tex]x^2-8x+15=0\\5^2-8(5)+15=0\\25-40+15=0\\0=0\\3^2-8(3)+15=0\\9-24+15=0\\0=0[/tex]
Hope this helps you understand how to do this by yourself. Now to do the rest ;-;
