I need serious help with solving this problem.
A 12.2 M solution has a volume of 4.0 L. The volume is doubled by adding water. What is the final molarity of the solution?

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Lanuel

The final molarity of this diluted solution is equal to 6.0 M.

Given the following data:

  • Initial volume = 4.0 mL
  • Initial molarity = 12.2 M
  • Final volume = 8.0 mL

To calculate the final molarity of this diluted solution:

The formula for the molarity of a solution.

Mathematically, the relationship between the molarity of a solution and volume is given by the formula:

[tex]MV = k\\\\M_1V_1 = M_2V_2[/tex]

Where:

  • M is the molarity of a solution.
  • V is the volume of a solution.

Making [tex]M_2[/tex] the subject of formula, we have:

[tex]M_2 = \frac{M_1V_1}{V_2}[/tex]

Substituting the given parameters into the formula, we have;

[tex]M_2 = \frac{12 \times 4.0}{8.0} \\\\M_2 = \frac{48}{8.0}[/tex]

Final molarity = 6.0 M

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