[tex]\huge \sf༆ Answer ༄[/tex]
According to the question ;
[tex]{ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:y \propto x[/tex]
Now, let's add a constant of proportionality to replace proportionality sign with equal to :
[tex]{ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:y = kx[/tex]
[ where, k is proportionality constant ]
plug the value of x and y from any ordered pair in the table , for example : [tex] \sf(\dfrac{1}{5} , 2)[/tex]
[tex]{ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:2 = k \times \dfrac{1}{5} [/tex]
[tex]{ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:k = 2 \times 5[/tex]
[tex]{ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:k = 10[/tex]
Therefore, value of proportionality constant (k) is
[tex]\overbrace{ \underbrace{\underline{ \boxed{ \sf 10 }}}}[/tex]
