Given:-
- Hypotenuse = √65
- Base = 4
- Perpendicular = ?
Solution:-
By Pythagoras theorem
[tex]H ^{2} = P^{2} + B ^{2} [/tex]
[tex]( \sqrt{65} ) ^{2} = P ^{2} + 4 ^{2} [/tex]
[tex]65 = P^{2} + 16[/tex]
[tex]P^{2} = 65 - 16[/tex]
[tex]P^{2} = 49[/tex]
[tex]P= \sqrt{49} [/tex]
[tex]P = 7[/tex]
- Thus, The length of Perpendicular is 7..
