Answer:
decreases by 1/9
Explanation:
the equation of kinetic energy is [tex]KE = \frac{mv^2}{2}\\[/tex]
here, we see that Kinetic Energy and v (velocity) are on opposide sides of the equation, this means that they are directly proportional (when one increases, the other one must increase (assuming mass (m) is constant)): KE∝[tex]v^2[/tex]
since V is decreasing by factor of 1/3, simply plug it in for v^2 to get (1/3)^2,
this equals (1/9). So KE will become 1/9 of original value
