contestada

A poll was conducted using an SRS of 180 self identified viewers of the E! Network. The poll asked people to pick their favorite Jenner. Of the 180 polled, 84 indicated they liked Kylie best.

Construct a 98% confidence interval to estimate the proportion of E! viewers who like Kylie Jenner best.

1. Identify

2. Conditions

3. Calculation

4. Interpret

Respuesta :

The 98% confidence interval to estimate the proportion of E! viewers who like Kylie Jenner best is; CI = (0.3801, 0.5533)

Confidence Interval

The formula for confidence interval for proportion is;

CI = p^ ± z√(p^(1 - p^)/n)

Where;

  • p^ is sample proportion
  • n is sample size
  • z is critical value at confidence level

We are given;

n = 180

p^ = x/n = 84/80

p^ = 0.467

Now the z-score at confidence level of 98% is;

z = 2.33

Thus;

CI = 0.467 ± 2.33√(0.467(1 - 0.467)/180)

CI = 0.4667 ± 0.0866

CI = (0.4667 - 0.0866), (0.4667 + 0.0866)

CI = 0.3801, 0.5533

Read more about confidence interval for proportion at; https://brainly.com/question/16427118

Otras preguntas