The circle below is centered at the point (-1,2) and has a radius of length 3. What is its equation?
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(x-h)²+(y-k)²=r²
when the center is (h,k) and the radius is r
given
(-1,2) and r=3
(x-(-1))²+(y-2)²=3²
(x+1)²+(y-2)²=3²
C is answer
Answer:
Option C is correct.
Step-by-step explanation:
We have been given the center of circle: (-1,2) and radius of length 3.
The general equation of circle is:
[tex](x-h)^2+(y-k)^2=r^2[/tex]
Here, h= -1, k=2 and r=3
h and k is the center of circle
On substituting the values in the formula we get:
[tex](x-(-1))^2+(y-2)^2=3^2[/tex]
[tex]\Rightarrow (x+1)^2+(y-2)^2=9[/tex]
Therefore, Option C is correct.