Answer:
[tex]y=\frac{6}{13}x+\frac{107}{13}[/tex]
Step-by-step explanation:
(x1, y1) = (-7, 5)
(x2, y2) = (6, 11)
The firs thing to do is fine the slope. That is the distance between the y-coordinates divided by the distance between the x-coordinates:
[tex]m=\frac{y2-y1}{x2-x1}[/tex]
I marked the points above as points 1 and 2, so you can plug those numbers into the formula:
[tex]m=\frac{11-5}{6--7}\\\\m=\frac{6}{13}[/tex]
That fraction can't be simplified any further, so the slope of this line is 6/13. The next thing to do is to find the y-intercept.
[tex]y=mx+b[/tex]
Plug the slope and any point of your choice into the equation. I'll use point b:
[tex]11=(\frac{6}{13})6+b[/tex]
Now, solve for b:
[tex]11=\frac{36}{13}+b\\\\11-\frac{36}{13}=b\\\\\frac{143}{13}-\frac{36}{13}=b\\\\\frac{107}{13}=b\\\\b=\frac{107}{13}[/tex]
They're far from clean, but those are the correct slope and y-intercept. Using those, the equation for this line is:
[tex]y=\frac{6}{13}x+\frac{107}{13}[/tex]
You can confirm that this is the correct equation by checking it with one of the points. Plug in one of the known values of x and make sure it gives the correct value of y:
[tex]y=\frac{6}{13}(-7)+\frac{107}{13}\\\\y=\frac{-42}{13}+\frac{107}{13}\\\\y=\frac{65}{13}\\\\y=5[/tex]
That works out.
