The value of f(15), to the nearest hundredth is 253.88
The standard exponential equation is given as:
If f(4.5) = 16, then;
16 = ab^4.5 ..............1
Similarly, if f(9.5) = 60, then:
60 = ab^9.5 ........................... 2
Dividing both equations will give:
60/16 = ab^9.5/ab^4.5
60/16 = b^9.5-4.5
60/16 = b^5
3.75 = b^5
b = 1.3
Get the value of a. Recall that;
60 = ab^9.5
60 = a(1.3)^9.5
60 = 12.09a
a = 60/12.09
a = 4.96
Get the value of f(15)
f()15 = 4.96(1.3)^15
f(15) = 4.96(51.18)
f(15) = 253.88
Hence the value of f(15), to the nearest hundredth is 253.88
Learn more on exponential functions here: https://brainly.com/question/12940982
