The force exerted on the cart 2 during the collision is 2 N.
The given parameters:
According to Newton's third law of motion, action and reaction are equal and opposite. The force exerted on cart 1 is equal in magnitude to the force exerted on cart 2 but in opposite direction.
[tex]F_1 = -F_2[/tex]
[tex]F_2 = -F_1\\\\F_2 = -2 \ N\\\\|F_2| = 2 \ N[/tex]
Thus, the force exerted on the cart 2 during the collision is 2 N.
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