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Trevor is fishing from a small boat. His fishing hook is 8 meters below him, and a fish is swimming at the same depth as the hook, 5 meters away. How far away is Trevor from the fish? If necessary, round to the nearest tenth.

Respuesta :

A ray from Trevor to the fish is the hypotenuse side of a right triangle  with

vertices at Trevor's position, the hook and the fish.

  • The distance from Trevor to the fish is approximately 9.4 meters.

Reasons:

The distance of the hook below Trevor, y = 8 meters

The horizontal distance of the fish from the hook, x = 5 meters

Required:

The distance of the fish from Trevor

Solution:

A line drawn from Trevor's position to the fish, h, then to the hook, x, and

then to Trevor, y, forms a right triangle with the distance from Trevor to the

fish being the hypotenuse side, h.

Therefore, by Pythagorean theorem, we have;

  • h² = y² + x²

Which gives;

h² = 8² + 5²

h = √(8² + 5²) = √(89 ≈ 9.4

  • The distance from Trevor to the fish given to the nearest tenth , d ≈ 9.4 meters

Learn more about Pythagorean theorem here:

https://brainly.com/question/18206420

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