Respuesta :
The accurate statements are:
- b. The circumference of the clock is approximately 62.8 inches.
- c. The minor arc measure when one hand points at 12 and the other hand points at 4 is 120°.
- e. The length of the minor arc between 6 and 7 is approximately 5.2 inches.
The given parameters are:
[tex]n = 12[/tex] --- number of parts
[tex]r = 10[/tex] --- the radius
(a) The central angle
Between points 1 and 3, there are 2 sections, each of which has a measure of 30 degrees.
So, the measure of the two sections is:
[tex]\theta = 30^o \times 2[/tex]
[tex]\theta = 60^o[/tex]
Hence, (a) is false
(b) The circumference
This is calculated using:
[tex]C = 2\pi r[/tex]
So, we have:
[tex]C = 2 \times 3.14\times 10[/tex]
[tex]C = 62.8[/tex]
Hence, (b) is true
(c) The measure of the minor arc
Between points 12 and 4, there are 4 sections, each of which has a measure of 30 degrees.
So, the measure of the four sections is:
[tex]\theta = 30^o \times 4[/tex]
[tex]\theta = 120^o[/tex]
Hence, (c) is true
(d) The length of the major arc
Between points 3 and 10, there are 7 sections, each of which has a measure of 30 degrees.
So, the measure of the seven sections is:
[tex]\theta = 30^o \times 7[/tex]
[tex]\theta = 210^o[/tex]
The length of the arc is:
[tex]L = \frac{\theta}{360} \times 2\pi r[/tex]
So, we have:
[tex]L = \frac{210}{360} \times 2 \times 3.14 \times 10[/tex]
[tex]L = \frac{13188}{360}[/tex]
[tex]L = 36.3[/tex]
Hence, (d) is false
(e) The length of the minor arc
There is only one section between points 6 and 7
So, the measure of the section is:
[tex]\theta = 30^o[/tex]
The length of the arc is:
[tex]L = \frac{\theta}{360} \times 2\pi r[/tex]
So, we have:
[tex]L = \frac{30}{360} \times 2 \times 3.14 \times 10[/tex]
[tex]L = \frac{1884}{360}[/tex]
[tex]L = 5.2[/tex]
Hence, (e) is true
Read more about segments and arcs at:
https://brainly.com/question/14965059
Answer:
-B
-C
-E
Step-by-step explanation:
just took the test...
I got them right
