Answer:
C. [tex]a_n=(9)(\frac{2}{3})^{n-1}[/tex]
Step-by-step explanation:
Iterative geometric sequence:
[tex]a_n=a_1x^{n-1}[/tex]
Recursive geometric sequence:
[tex]a_n=xa_{n-1}[/tex]
The equations are very similar and you only really need to rearrange it. The factor (2/3) and the first term (9) are given, so you can write the iterative equation:
[tex]a_n=(9)(\frac{2}{3})^{n-1}[/tex]
And so the answer is C.
