Find the height of the building below by using your knowledge of trigonometry.
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Answer:
50[tex]\sqrt{3}[/tex]
Step-by-step explanation:
The figure represents a 30-60-90 special triangle
in this special right triangle the measure of sides lengths is represented by
a, a[tex]\sqrt{3}[/tex], and 2a
The side length that sees angle measure 30 is represented by a and here we see a = 50m
The height of the building, which sees angle measure 60, is equal to
50[tex]\sqrt{3}[/tex]