Respuesta :
Answer:
1 s
Explanation:
The speed of the sound, distance travelled and the time taken relationship is given as follows.
Speedofsound,v=Distancetravelled×Timetaken ----eqn 1
With the given values of wavelength = 50 cm = 0.5 m and frequency =1000 Hz, the speed of the wave is calculated as follows.
Speedofsound,v=Frequency(ν)×Wavelength(λ) -- eqn 2
That is, v=ν×λ=1000Hz×0.5m=500m/s
Substituting the value of the speed of sound in eqn 1 gives the time taken for the sound wave to travel a distance of 500 m.
That is, Timetaken=
Distancetravelled
Speedofsound
=
500m
500m/s
=1second.
Hence, the time taken for the sound wave to travel is 1 second.
The speed with which the waves will be travelling is 12.5m/s.
Given the data in the question;
- Frequency; [tex]f = 25\ waves\ per\ second = 25s^{-1}[/tex]
- Wavelength; [tex]\lambda = 50cm = 0.5m[/tex]
Speed of the wave; [tex]v =\ ?[/tex]
To determine how fast the waves will be travelling, we use the expression for the relations between wavelength, frequency and speed of wave.
[tex]\lambda = \frac{v}{f}[/tex]
Where [tex]\lambda[/tex] is wavelength, f is frequency and v is speed of wave
We substitute our values into the equation
[tex]0.5m = \frac{v}{25s^{-1}} \\\\v = 0.5m * 25s^{-1}\\\\v = 12.5ms^{-1}[/tex]
Therefore, the speed with which the waves will be travelling is 12.5m/s.
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