Respuesta :

Answer:  

1 s

Explanation:

The speed of the sound, distance travelled and the time taken relationship is given as follows.

Speedofsound,v=Distancetravelled×Timetaken ----eqn 1

With the given values of wavelength = 50 cm = 0.5 m and frequency =1000 Hz, the speed of the wave is calculated as follows.

Speedofsound,v=Frequency(ν)×Wavelength(λ) -- eqn 2

That is, v=ν×λ=1000Hz×0.5m=500m/s

Substituting the value of the speed of sound in eqn 1 gives the time taken for the sound wave to travel a distance of 500 m.

That is, Timetaken=

Distancetravelled

Speedofsound

=

500m

500m/s

=1second.

Hence, the time taken for the sound wave to travel is 1 second.

The speed with which the waves will be travelling is 12.5m/s.

Given the data in the question;

  • Frequency; [tex]f = 25\ waves\ per\ second = 25s^{-1}[/tex]
  • Wavelength; [tex]\lambda = 50cm = 0.5m[/tex]

Speed of the wave; [tex]v =\ ?[/tex]

To determine how fast the waves will be travelling, we use the expression for the relations between wavelength, frequency and speed of wave.

[tex]\lambda = \frac{v}{f}[/tex]

Where [tex]\lambda[/tex] is wavelength, f is frequency and v is speed of wave

We substitute our values into the equation

[tex]0.5m = \frac{v}{25s^{-1}} \\\\v = 0.5m * 25s^{-1}\\\\v = 12.5ms^{-1}[/tex]

Therefore, the speed with which the waves will be travelling is 12.5m/s.

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