This question is mentioning an experiment that is not being described about the volume of the propane gas in an Erlenmeyer before the addition of water.
In this case, since no information is given, it is possible to propose a suggested procedure of how to figure it out via gas laws, specifically, the ideal gas one, since no change is decribed before the addition of water:
[tex]PV=nRT[/tex]
Thus, you can solve for the volume, by dividing both sides by the pressure, so that you will get:
[tex]V=\frac{nRT}{P}[/tex]
Now, to ensure a correct calculation, make sure you have the moles (divide by the molar mass of propane, 44,1 g/mol, if you were given the grams), the temperature in K (add 273.15 if you have degree Celsius), the ideas gas constant as 0.08206 and the pressure in atm, in order to have consistent units.
If you need the volume in milliliters, you will need to multiply the previous answer by 1000 in order to perform the appropriate conversion.
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