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What is the molarity of a NaOH solution if 48.0 mL of a 0.220 M H2SO4 solution is required to neutralize a 25.0-mL sample of the NaOH solution?

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Answer:

Molarity NaOH = 0.85M (2 sig figs)

Explanation:

48.0ml(0.220M H₂SO₄) + 25ml(Xmolar NaOH)H₂SO₄ + 2NaOH => Na₂SO₄ + 2H₂O

2(molarity x volume) H₂SO₄ = (molarity x volume) NaOH

2(0.220M x 48.0ml) = 25.0ml x Molarity NaOH

Molarity NaOH = 2(0.220M x 48.0ml)/25.0ml = 0.8448M ≅ 0.85M (2 sig figs)

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