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A small balloon at standard temperature has a volume of 80.0mL. When placed into a Dewar flask of liquid nitrogen (-200C), it contracts. What is the balloon’s new volume?

Respuesta :

pstnonsonjoku

Since the temperature is directly proportional to volume, the new volume of the gas is 21.4 mL.

We have the following information;

Initial temperature(T1) = 273 K

Initial volume (V1) = 80.0mL

Final temperature (T2)= -200°C + 273 = 73 K

Final volume (V2) = ?

Using the relation of Charles' law;

V1/T1 = V2/T2

V1T2 = V2T1

V2 = V1T2 /T1

V2 = 80.0mL ×  73 K/ 273 K

V2 = 21.4 mL

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