Answer:
[tex]x=3[/tex];[tex]y=\frac54[/tex]
Step-by-step explanation:
You have 4y on both. So unless you're asked to use a specific method, just subtract one from the other.
[tex]II - I: 5x+4y-3x-4y = 20-14\\2x = 6 \rightarrow x=3[/tex]
Now you have two options: you eliminate x by multiplying the first by 5, the second by 3, and subtracting again, or you plug the value you found in one of the two. Let's do that, using the second
[tex]5(3)+4y=20 \rightarrow 15+4y = 20\\4y = 5\rightarrow y=\frac 54[/tex]
