[tex]~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$300\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually means once} \end{array}\dotfill &1\\ t=years\dotfill &10 \end{cases} \\\\\\ A=300\left(1+\frac{0.05}{1}\right)^{1\cdot 10}\implies A=300(1.05)^{10}\implies A\approx 488.67[/tex]
